calculating from hp, torque, and rpm how much mass a vibrating motor w
calculating from hp, torque, and rpm how much mass a vibrating motor w
(OP)
EE by degree and thrown into this problem.
Need formulas for how much mass a vibrating motor will move.
known are the characteristics of the motor.
Hp
Torque
rpm
Any help appreciated
Many Thanks
MidniteRambler
Need formulas for how much mass a vibrating motor will move.
known are the characteristics of the motor.
Hp
Torque
rpm
Any help appreciated
Many Thanks
MidniteRambler





RE: calculating from hp, torque, and rpm how much mass a vibrating motor w
RE: calculating from hp, torque, and rpm how much mass a vibrating motor w
The mass to be shaken is the case for the motor andthe accompanying electronics.
Good question, I should have had that in there at first!!
Many Thanks,
MidniteRambler
RE: calculating from hp, torque, and rpm how much mass a vibrating motor w
Depending on the dynamics of the system (masses, other springs, and frequencies), the force transferred to the person may be less.
The ability of a person to sense vibration undoubtedly depends on frequency (motor speed) as well.
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RE: calculating from hp, torque, and rpm how much mass a vibrating motor w
I'd cheat and first measure the vibration (frequency and amplitude) of nice devices' buzz alarm.
RE: calculating from hp, torque, and rpm how much mass a vibrating motor w
Then you have the "ideal" frequency and amplitude for a vibration alarm. The frequency is easy to scale to what ever mass you need (should be the same).
You can reproduce the amplitude by comparing the force (m*r*w^2) of the vibrator to the mass (resistance to move) of the vibratee (electronics, housing, battery, etc.) You should then know the m*r needed (w is based on frequency). Increase m and decrease r or decrease m and increase r as desired (i.e. big r little m = light weight; big m little r = small).
The motor RPM will be known (frequency desired) and the motor torque will be whatever is needed to maintain acceleration (r*w^2) of the m selected to produce the desired force (force = m*a).
I may have missed something but someone more skilled (and more awake) then I will hopefully correct it.