Expected Overall Compliance
Expected Overall Compliance
(OP)
Dear All,
If I test a Sample of Material with multiple specified parameters I can calculate the expected compliance for each parameter.
e.g.
Parameter 1 is expected to comply 90% of the time
Parameter 2 is expected to comply 95% of the time
Parameter 3 is expected to comply 85% of the time
If any parameter fails the overall result for a Sample fails.
So from the above information is it possible to calculate the expected compliance of a Sample with all respect to all parameters?
TIA Hugh
If I test a Sample of Material with multiple specified parameters I can calculate the expected compliance for each parameter.
e.g.
Parameter 1 is expected to comply 90% of the time
Parameter 2 is expected to comply 95% of the time
Parameter 3 is expected to comply 85% of the time
If any parameter fails the overall result for a Sample fails.
So from the above information is it possible to calculate the expected compliance of a Sample with all respect to all parameters?
TIA Hugh





RE: Expected Overall Compliance
If they are truly independent then the probability of a pass is 73%
Cheers
Greg Locock
Please see FAQ731-376 for tips on how to make the best use of Eng-Tips.
RE: Expected Overall Compliance
Thanks for the response
I think I get and grasp your logic and get an answer of 72.675%
Thus;
85% - (85% of 10%) = 85% - 8.5% = 76.5%
76.5% - (76.5% of 5%) = 76.5% - 3.825% = 72.675% (=73ish%)
Am I correct in this?
The parameters are not independent (of course)!
Kind regards Hugh,
RE: Expected Overall Compliance
In the old days
p(A AND B AND C)=p(A)*p(B)*p(C)
If they are not independent and you understand the physical dependency then Monte Carlo modelling is often a good way to understand what is going on.
If on the other hand you just have a statistical description of the interrelationship then draw a Venn diagram and sum appropriately.
Cheers
Greg Locock
Please see FAQ731-376 for tips on how to make the best use of Eng-Tips.
RE: Expected Overall Compliance
Thanks for your help again.
p(A)*p(B)*p(C) looks less complicated.
Seems I am going through 'old days' without actually having lived them!
Much appreciated.
regards Hugh
RE: Expected Overall Compliance
Regards,