HP to wheel size conversion
HP to wheel size conversion
(OP)
I am trying to turn a generator which requires 30hp to turn at 500rpm. What amount of Force or Torque (I am not sure what the best measurement would be) would I need to apply to a 2 inch shaft to achieve this?
The shaft will be attached to a 2 ft diamter steel wheel pulley.
Thanks for any help-
820currie
The shaft will be attached to a 2 ft diamter steel wheel pulley.
Thanks for any help-
820currie





RE: HP to wheel size conversion
The answer to your question is:-
power= 2*pi*N*T/60
were power = 30hp*746watts
pi=3.142
N=rpm
T=torque (Newton metres)
rearranging the formula we get:-
T= power*60/(2*pi*500) T= 427.426 Nm = 3773.822lbin
if your applying your torque to the 2FT pulley
then the force you need to exert
is 3773.822lbin/12in" = 314.5lbf
regards desertfox
RE: HP to wheel size conversion
Thanks a bunch for the help.
Sanity question. It sounds like 315 lbf is pretty extreme. Should I get a bigger pully or something to help reduce the amount of force required? Would that help? Is there a formula to use to help reduce the amount of force required to turn this object?
Thanks for your help.
820currie
RE: HP to wheel size conversion
You can reduce the force req by increasing the pulley radius.
torque= force * radius.
However if you change the pulley size you will have to also change the pulley size with which you drive it with.
regards desertfox