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HP to wheel size conversion

HP to wheel size conversion

HP to wheel size conversion

(OP)
I am trying to turn a generator which requires 30hp to turn at 500rpm.  What amount of Force or Torque (I am not sure what the best measurement would be) would I need to apply to a 2 inch shaft to achieve this?

  The shaft will be attached to a 2 ft diamter steel wheel pulley.

Thanks for any help-
820currie

RE: HP to wheel size conversion

Hi 820currie

The answer to your question is:-

power= 2*pi*N*T/60

were power = 30hp*746watts

pi=3.142

N=rpm

T=torque (Newton metres)


rearranging the formula we get:-


T= power*60/(2*pi*500)  T= 427.426 Nm = 3773.822lbin

if your applying your torque to the 2FT  pulley

then the force you need to exert
is 3773.822lbin/12in" = 314.5lbf

regards desertfox

RE: HP to wheel size conversion

(OP)
desertfox:

  Thanks a bunch for the help.

  Sanity question.  It sounds like 315 lbf is pretty extreme.  Should I get a bigger pully or something to help reduce the amount of force required?  Would that help?  Is there a formula to use to help reduce the amount of force required to turn this object?


Thanks for your help.
820currie

RE: HP to wheel size conversion

Hi 820currie

You can reduce the force req by increasing the pulley radius.

torque= force * radius.

However if you change the pulley size you will have to also change the pulley size with which you drive it with.

regards desertfox

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