Sodium BiSulfite Pump Design
Sodium BiSulfite Pump Design
(OP)
I am working on a Sodium BiSulfite Pump Skid design for dechlorination and as per my research, for every 1 mg/L of total chlroine, 1.63 mg/L of SBS is needed to reduce total chlorine residual to Zero.
Assuming I have 700 gpm of flow with 1 mg/L of total chlorine, what would be my pump rate for SBS which is available in aqueous solution.
Somewhere, I have seen an example and trying to figure out how they came up with this one.
At max designed flow rate of 5 MGD, 27.2 gal/day of SBS is required for every 1 mg/L of total chlorine. How did they cam up with this using above concentration levels?
Can anyone help me?
Thanks
Assuming I have 700 gpm of flow with 1 mg/L of total chlorine, what would be my pump rate for SBS which is available in aqueous solution.
Somewhere, I have seen an example and trying to figure out how they came up with this one.
At max designed flow rate of 5 MGD, 27.2 gal/day of SBS is required for every 1 mg/L of total chlorine. How did they cam up with this using above concentration levels?
Can anyone help me?
Thanks





RE: Sodium BiSulfite Pump Design
700 GPM = 2,650 liters/min flow.
At 1 mg/l chlorine = 2,650 mg/min chlorine.
2,650 mg/min chlorine X 1.63 = 4,320 mg/min requirement for sodium bisulfite.
Based on your pump's capacity, choose a mid-range discharge volume and develop a sodium bisulfite-water solution that will deliver 4,320 mg/min to the 700 gpm water flow at that pump output.
Orenda
RE: Sodium BiSulfite Pump Design
From this info & knowing the 1.63 SBS/chlorine (by weight) ratio, calculate the concentration of the SBS treatment solution:
At a max 5 MGD, per 1 mg chlorine/Liter (3.7853 mg chlorine/gallon), need 27.2 gal/day of SBS solution.
So 18,926,500 mg chlorine requires x 1.63 (SBS/chlorine) = 30,850,195 mg SBS, or 30,850 grams SBS.
Since the SBS is dissolved in 27.2 gallons of water, its concentration is 30,850 grams/27.2 gallons
Concentration of SBS treatment solution
= 1134 grams/gallon
= 2.5 pounds SBS/gallon
= 300 grams/Liter.
Now, back to first part of question.
As 700 gpm @ 1 mg chlorine/L requires 4.319 grams SBS/min,
the required SBS treatment solution is
(4.319 grams SBS/min)/(300 grams SBS/L) = 0.0144 L/min (14.4 mls/min).
You could use a peristaltic pump of 25 mls/min capacity (1.5 L/hr).
Or, for more uniform dosing, dilute the SBS solution by a factor of 10, to 30 grams/Liter, giving a higher flow requirement of 144 mls/min. Then use an electric, diapragm-type metering pump of capacity 300 mls/min (18 Liters/hr (4.76 gallons/hr).
Ken
RE: Sodium BiSulfite Pump Design
It depends upon what concentration SMBS they are using. 27.2gpd is 102.96 lpd. As per your testing result(1.63ppm of SMBS for 1 ppm of chlorine), it comes to be 30.85 kgs/day.
If the SMBS concentration is 30%w/v then 102.96 lpd is 0.3*102.96 = 30.88 kgs/day. However, commercially available concentration, in India, is about 65%w/v. So, it is better to check at what concentration the solution is prepared.