Motor / Pump cooling.
Motor / Pump cooling.
(OP)
Motor and pump cooling application:
Would it be safe to assume that the difference between brake hp and water hp equals the power loss through the application?
This loss will equal the heat that the pump and motor will create and must be removed / cooled.
Example:
100% duty cycle.
Water hp to deliver X gallons @ X head = 75 hp.
Brake hp to deliver the same @ same = 100 hp
Difference equals 25 hp of heat to dissipate.
Is it this simple? What am I missing?
TM
Would it be safe to assume that the difference between brake hp and water hp equals the power loss through the application?
This loss will equal the heat that the pump and motor will create and must be removed / cooled.
Example:
100% duty cycle.
Water hp to deliver X gallons @ X head = 75 hp.
Brake hp to deliver the same @ same = 100 hp
Difference equals 25 hp of heat to dissipate.
Is it this simple? What am I missing?
TM





RE: Motor / Pump cooling.
Brake Hp X 0.746 = kW mechanical power delivered at motor shaft. KW at motor shaft / motor efficiency = electrical kW input at motor terminals. Motor shaft kW - terminal kW = heat transferred to ambient from the motor.
RE: Motor / Pump cooling.