Fixed End or Zero Tolerance Load Distribution
Fixed End or Zero Tolerance Load Distribution
(OP)
Can anyone explain how gravity beam loads get distributed into a fully fixed end or a zero tolerance type fitting. I have seen it assumed as an triangular distribution with the higher ends of the triangle opposing one another on each end. Any help would be appreciated.





RE: Fixed End or Zero Tolerance Load Distribution
RE: Fixed End or Zero Tolerance Load Distribution
RE: Fixed End or Zero Tolerance Load Distribution
RE: Fixed End or Zero Tolerance Load Distribution
a = (Le/6)(3L+4Le)/(L+Le).
w2 = (w1)(L)(3L+4Le)/(Le^2).
w3 = (w2)[1-(Le/a)].
RE: Fixed End or Zero Tolerance Load Distribution
Nice Job. Thanks.
RE: Fixed End or Zero Tolerance Load Distribution
I think you meant your w3 is downwards not upwards. If you have Joseph Shelleys Volume 1 Statics book by Schaums its on page 553. Thanks.
RE: Fixed End or Zero Tolerance Load Distribution
By the way, using a rigid-body mechanics solution, such as in my previous post, is reasonable only if the beam is relatively stiff compared to the embedment material. If, instead, the beam is relatively flexible compared to the embedment stiffness, the load will transfer more rapidly to the embedment material, such that embedment beyond a certain distance becomes ineffective. In other words, if the beam is relatively flexible, then one can't ignore elasticity and compliance, and the problem becomes more complicated, in which case you could use, e.g., finite element and surface contact to solve the problem.
RE: Fixed End or Zero Tolerance Load Distribution
If you have the PCI Design Handbook 3rd edition pgs 6-26 and 6-68 have a lot of conditions already calculated in a nice tabular form. If you do any precast or prestressed concrete this book is a must. Thanks Again for the Tips.