## Condensing turbine calculation

## Condensing turbine calculation

(OP)

Hi,

I would like to know how to calculate the cogeneration potential (electricity generation) that is possible to achieve with a given steam condensing turbine at some efficiency. In this case, with efficiency I mean the MWh produced per MMBTU of energy extracted from the steam.

Let's say I have 27.2 ton/h (60 klb/h) of saturated steam at 2.4 bar (35psi) going into the turbine and an outlet pressure of 0.15 bar.

Is 0.15 bar a usual outlet pressure for a steam condensing turbine?

What is a typical efficiency value (in MWh/MMBTU extracted)?

How much energy is extracted from the steam that can be converted to electricity under these circumstances?

How do I go about calculating this amount of energy?

Many thanks,

mat

I would like to know how to calculate the cogeneration potential (electricity generation) that is possible to achieve with a given steam condensing turbine at some efficiency. In this case, with efficiency I mean the MWh produced per MMBTU of energy extracted from the steam.

Let's say I have 27.2 ton/h (60 klb/h) of saturated steam at 2.4 bar (35psi) going into the turbine and an outlet pressure of 0.15 bar.

Is 0.15 bar a usual outlet pressure for a steam condensing turbine?

What is a typical efficiency value (in MWh/MMBTU extracted)?

How much energy is extracted from the steam that can be converted to electricity under these circumstances?

How do I go about calculating this amount of energy?

Many thanks,

mat

## RE: Condensing turbine calculation

rmw

## RE: Condensing turbine calculation

Let's define a few terms

h1=enthalpy of sat steam

s1=entropy of saturated steam

h2=enthalpy at condenser

hs2=isentropic enthalpy at condenser

m=mass flow of steam

x=quality at condenser (isentropic)

sg=saturated gas entropy at condenser pressure

sf=satruated liquid entropy at condenser pressure

hg= saturated gas enthalpy

hf=saturated liquid enthalpy

e=isentropic efficiency (ussually in the range of 80-86%)

1. Determine quality and h2s using pressure at condenser and s1.

x=(s1-sf)/(sg-sf)

h2s=x*(hg-hf)+hf

2. Determine real enthalpy

h2=h1-e*(h1-h2s)

3. Power= m*(h1-h2)

So for your conditions:

h1=2717 kJ/kg

s1=7.053 kJ/kg-K

I would assume a condenser pressure of about 0.07 bara

hg=2572

hf=163

sg=8.274

sf=0.559

Assume an efficiency of about e=80%

therefore

x=(7.053-0.559)/(8.274-0.559)=0.84

hs2=0.84*(2572-163)+163=2191

h2=2572-0.8*(2572-2191)=2267

Power=27.2*(2572-2267)/3600=2.3 MW

## RE: Condensing turbine calculation

I like your "old fashion" way of determining the energy extracted but could you check your calculations for h2 and Power? It looks like you inadvertently picked up "hg" in those calculations instead of using "h1" as indicated in your procedure. I think that what you have outlined in the steps of your procedure is correct but I wanted to make sure.

## RE: Condensing turbine calculation

## RE: Condensing turbine calculation

The calculation should be

h2=2717-0.8*(2717-2191)=2296 kJ/kg

P=27.2*(2717-2296)/3.6=3.2 MW

A note about isentropic efficiencies: I am used to dealing with steam turbines in a much higher power range (30 MW to 100 MW). These machines tend to have quite high isentropic efficiencies (in the range of 83-86%). I am taking an educated guess on the efficiency of a turbine in the 2-3 MW range having an efficiency of about 80%, but I wouldn't be surprised if it was as low as 75% (although practically speaking it doesn't make a huge difference in the resulting power). Perhaps someone with more experience with turbines in this size range could "weigh in" with an answer?

## RE: Condensing turbine calculation