neutralization of nitric acid
neutralization of nitric acid
(OP)
When nitric acid HNO3 is neutralized by sodium hydroxide NaOH the byproduct is H2O and NaHO3. Lets say you mix one pound of each what would be the amount in weight of the H2O and the NaHO3?





RE: neutralization of nitric acid
Orenda
RE: neutralization of nitric acid
Thanks
RE: neutralization of nitric acid
The stoichiometric balancing equation:
shows: 40 + 63 = 85 + 18 = 103
RE: neutralization of nitric acid
Of course this only applies to strong acids and bases such as these...otherwise you have to take into account equilibrium constants (Ka's).
RE: neutralization of nitric acid
Of course you are correct....I must have been daydreaming and didn't read beyond the original question of 1 pound each of the reactants, which (ignoring the actual H2O and NaNO3 product weights) still results in a TOTAL of 2 pounds of material on the right side of the equation.
Sorry about that!
Orenda
RE: neutralization of nitric acid
Not so. Zoobie is right. On a stoichiometric basis and assuming all the acid is consumed, one lb of each reactant means 0.365 lb NaOH will remain unreacted, and the equation's right side products will amount to ~1.635 lb.
RE: neutralization of nitric acid
RE: neutralization of nitric acid
RE: neutralization of nitric acid
RE: neutralization of nitric acid
RE: neutralization of nitric acid
1.587HNO3+2.500NaOH= 2.044H2O+1.587NaNO3+.913Na+.456O
Do a mass balance and it checks out but instead of using 1lbs, I used 100lbs.. You get 36.8lbs of H2O and 134.9lbs of NaNO3
RE: neutralization of nitric acid
Great post. That is what I needed you are best today.
RE: neutralization of nitric acid
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