Reinforcement on a skewed bridge
Reinforcement on a skewed bridge
(OP)
hi,
i've post a question in an another forum :
http://www.eng-tips.com/viewthread.cfm?qid=154167
but will i have more chance to get a response here !?
thanks :)
i've post a question in an another forum :
http://www.eng-tips.com/viewthread.cfm?qid=154167
but will i have more chance to get a response here !?
thanks :)





RE: Reinforcement on a skewed bridge
At least in that method the reinforcing remains the same and the steel can be ordered full length and cut to fit in the fab shop.
THere are other ways of handling this but this is most common.
Regards,

Qshake
Eng-Tips Forums:Real Solutions for Real Problems Really Quick.
RE: Reinforcement on a skewed bridge
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RE: Reinforcement on a skewed bridge
RE: Reinforcement on a skewed bridge
? = angle in between principal moments (M1) and direction of reinforcement
? = angle in between directions of reinforcement ? and ?
Mu = M1 sin^2(?- ?) + M2 cos^2(?- ?)
M? = M1 sin^2 (?) + M2 cos^2(?)
M’’ = M1 sin ? sin(?- ?) - M2 cos ? cos(?- ?)
Substitute moments (to size the reinforcement)
Mu ‘= 1/ sin^2(?) (Mu +k? M’’?)
M? ‘= 1/ sin^2(?) (M? +1/k? M’’?)
When ? =90°
then
Mu = M1 cos^2(?) + M2 sin^2(?)
M? = M1 sin^2(?) + M2 cos^2(?)
M’’ = (M1 - M2) sin?cos?
Mu ‘= Mu +k? M’’?
M? ‘= M? +1/k? M’’?
The factor k should be approximately 1.
RE: Reinforcement on a skewed bridge
RE: Reinforcement on a skewed bridge
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RE: Reinforcement on a skewed bridge
? = angle in between principal moments (M1) and direction of reinforcement
? = angle in between directions of reinforcement ? and ?
Mu = M1 sin2(?- ?) + M2 cos2(?- ?)
M? = M1 sin2 ? + M2 cos2?
M’’ = M1 sin ? sin(?- ?) - M2 cos ? cos(?- ?)
Substitute moments (to size the reinforcement)
Mu ‘= 1/ sin2? (Mu +k? M’’?)
M? ‘= 1/ sin2? (M? +1/k? M’’?)
When ? =90°
then
Mu = M1 cos2 ? + M2 sin2 ?
M? = M1 sin2 ? + M2 cos2?
M’’ = (M1 - M2) sin? cos?
Mu ‘= Mu +k? M’’?
M? ‘= M? +1/k? M’’?
The factor k should be approximately = 1
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