blower motor power????
blower motor power????
(OP)
guys,,
how can i determine the blower shaft power?
how can i determine the blower shaft power?
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RE: blower motor power????
Meaure current and voltage?
Strain gages on the shaft?
Force transducers on the motor mounts?
Mike Halloran
Pembroke Pines, FL, USA
RE: blower motor power????
pump=Q(gpm)*H(ft)/pump eff.*3960
RE: blower motor power????
htt
Mike Halloran
Pembroke Pines, FL, USA
RE: blower motor power????
The above “rule of thumb” will need to be adjusted for fan efficiency.
RE: blower motor power????
__________________
6355 x Efficiency
HVAC68
RE: blower motor power????
I see that you have a different conversion factor in the denominator than I had. 6356 vs. 4100
This will make a big difference. So, I looked in some references:
“HVAC Equations, Data, and Rules of Thumb” by Arthur A. Bell gives 6356 on page 38
“Air-Conditioning Systems Design Manual” by ASHRAE gives 4100 on page 5-31
I haven’t cranked the numbers to find which factor is correct; however, this just shows how it is important to personally verify these cookbook rules of thumbs. I will drop a note after I make the calculations to verify which factor is correct.
Regards,
Zapster
RE: blower motor power????
Where: H = shaft power (W)
BE = input power(W)
and ? motor = motor efficiency
RE: blower motor power????
The formula for fans' power input is:
η is the efficiency as a ratio of fan output power to fan input power which includes losses due to skin friction, leakage and mechanical friction.
K is the compressibility coefficient, itself a function of the polytropic exponent, and the absolute total pressures at the inlet and outlet.
As to velocity head, in. wg, it is estimated from the air velocity in fpm, assuming air incompressible, 1 in. wg = 5.193 lb/ft2, gc = 32.174 ft.lbm/lb.s2, the formula is:
The divisor 4005 results from assuminmg dry air at 70oF and a pressure of 29.92 in. Hg with a density of 0.075 lb/ft3. It becomes 4100 when assuming moist-saturated air at 25oC.