Cooling Water Flow
Cooling Water Flow
(OP)
I'm trying to determine the amount of water flow I will need to cool a heated platen (350 to 70 deg) in 1 hour. The platen is made of stainless steel and is 48" by 48" by 4" thick. Water flows inside the platens.
Any help on equations that apply will be appreciated.
Any help on equations that apply will be appreciated.





RE: Cooling Water Flow
Mass = Vol*Density = 48x48x4/144 (40.8 lbs/ft^2*in) = 2611 lbs
Energy used to heat steel
kW = m*Cp*dT/3412*Hrs = 2611 lbs(0.12 Btu/lb/F)(350-70)/(3412*1hr) = 25.7 kWhr = 87688 Btu/hr
Energy gained by water to cool steel to say 150F
m = q/(Cp*dT) = 87688 Btu/hr / (1 Btu/lb/F)(150-70)
m = 1096 lbs/hr = 18.27 lbs/min / 8.31 lbs/gal = 2.2 gal/min.
I am not sure of all your system variables but this should be close enough.
RE: Cooling Water Flow