Generator L-G Fault
Generator L-G Fault
(OP)
Is there a quick back of the envelope type calculation for a generator line to ground fault at the terminals?
Thank You in advance
Thank You in advance
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RE: Generator L-G Fault
so I=E/(X1+X2+X0+3XN)
this is calculation for fault
RE: Generator L-G Fault
RE: Generator L-G Fault
For a 3-phase fault, I = E / 3X1. If E=1 and X1=1,
then I = 1 / 3 = 0.33.
For generators X1 is normally about the same as X2, but X0 is typically very much less.
If X1=X2, and say X0 = 0.1 X1,
then I = 1 / 2.1 = 0.48
I suspect your program doesn't have the correct X1, X2 and X0 values (you can't assume default values are correct). Also, this could be explained by a relatively high XN.
RE: Generator L-G Fault
RE: Generator L-G Fault
RE: Generator L-G Fault
RE: Generator L-G Fault
cheers !
RE: Generator L-G Fault
Because of the way the sequence networks parallel, a decent sized generator (say 2MW) in parallel with a comparable utility service produces an SLG fault value much higher than the sum of the two sources taken individually.
RE: Generator L-G Fault
As always, thanks to everyone and this is a great forum.