Heat Rejection of Pump
Heat Rejection of Pump
(OP)
Hello! I have a 2000 horsepower reciprocating pump, and I'm trying to determine how much horsepower is being dumped into the lube oil. I know the volume of the tank, the flow rate, the oil properties, and the beginning and ending temperatures over a 30 minute period of time. Where do I go from here???? Thanks for any help.





RE: Heat Rejection of Pump
If you are looking for the horsepower used then measure the amps that the pump is drawing. Then volts*amps = watts. Convert the watts to horsepower.
If you are looking for how much heat is added to the system then take heat capacity (Btu/lb/°F)* total amount of oil(lbs)*(Final temp - initial temp)/30min That will give you approximately Btu/min. It ignores the metal mass of the system and the current heat loss.
I assume you are looking to add an oil cooler or something?
Hope this helps.
StoneCold
RE: Heat Rejection of Pump
When you say "*total amount of oil*", do you mean the mass of oil that was circulated over the 30 minutes or the total mass that resides in the lube tank?
RE: Heat Rejection of Pump
What I meant was the total amount of oil in the system.
It does not matter how many times it goes around.
The heat is actually coming from the 90% mechanical efficiency on the pump. Friction of the oil pumping around is where the heat is coming from.
StoneCold
RE: Heat Rejection of Pump
RE: Heat Rejection of Pump