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NUMBER SEQUENCE HELP!!

NUMBER SEQUENCE HELP!!

NUMBER SEQUENCE HELP!!

(OP)
Can anyone help me find a formula to find the nth term of 1+2+3+4+5+6+7+8+....n = ???
i.e if n=8 then the answer is 36, so if for e.g i wanted to find the answer to n=1000 i can use a formula.
Thanks, not too sure if this is the right forum but there aren't a great deal of maths ones!

RE: NUMBER SEQUENCE HELP!!

(n)(n+1)/2

RE: NUMBER SEQUENCE HELP!!

(OP)
Thanks, dont suppose you could tell me how to work that out too?? I managed to guess it was a quadratic formula but couldnt work out a b or c values.

RE: NUMBER SEQUENCE HELP!!

Not exactly a 'proper' explanation, but you can look at the problem like this:
- adding up the first and the last number in a series gives (n+1),
- there is n/2 pairs like that,
- so to get a total sum, you just multiply (n+1)*n/2

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