×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!
  • Students Click Here

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

Jobs

Create Parabola in V5
2

Create Parabola in V5

Create Parabola in V5

(OP)
All,
Sort of a newbie question, how do you create a parabola? I did the conic method but I would like to input the focal length, is there a way?

Ross.

RE: Create Parabola in V5

If you want something exact, start with a sketch.  Then, using half of your parabola, you can define a law.

It's my preferred method

RE: Create Parabola in V5

2
In Sketcher, the first point is the focus and second one the vertex, so the distance between them is the focal length.
I've been constructing conics in Catia since Version 1, in 1983, and prefer to do it out of Sketcher, by calculating the points first, it doesn't really matter.

The equation of a Parabola (2D) is x = y^2 / 4*f , where f = Focal Length.

To construct one in V5 Space, which has a specific focal length, three points have to be calculated. These are the Start Point, End Point and the Tangent Intersection Point.

                                         

In the picture a parabola of 100 (units) focal length has been constructed on a Support (XY-plane) so that it's vertex is at the point(0,0,0) and the focus at (100,0,0).  In this example the start and end points are to have an arbitrary value of 400 so to find their y value the equation is transposed and x = 400 plugged into it. The  Focal Point is at the centre of the small circle.

                               y = (4 * f * x )^0.5

Therefore                y = 400

The tangent intersection point is on the X-axis at the negative value of the start and end points.

Thus, the three points required to make a 100 focal length parabola are,

            Start Point = ( 400, 400,0 )
             End Point = ( 400,-400,0)
     Tangent Intersection Point = (-400,0,0)

This is not done in Sketcher, but in 3D.

Select Insert => Wireframe => Conic

Support = XY-plane. then enter the above values and apply, accept the 0.5 Parameter. This gives a parabola, parameter values above and below 0.5 will fit hyperbolic or elliptical curves to the given input.

The tangent intersection point does not have to used, lines having the same direction as the tangents can be selected. It is sometimes better to make more of a parabola than is required and trim it back. To make one that is not symmetrical about it's own axis, without trimming, means a more complicated calculation.

The same principle is used to make conic surfaces, the tangents are to existing surfaces or their intersection is a curve.











RE: Create Parabola in V5

The methods above are better but I thought I'd add that you can also use a parallel curve driven by a law.

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members!


Resources