Simple maths
Simple maths
(OP)
I am trying to simplify the following
[(1/x)]-x
into a single variable of x i.e.:
[(1/x)]-x = ?x?
Any ideas? (This is for my work and is NOT a school homework question.)
Cheers,
-- drej --
[(1/x)]-x
into a single variable of x i.e.:
[(1/x)]-x = ?x?
Any ideas? (This is for my work and is NOT a school homework question.)
Cheers,
-- drej --





RE: Simple maths
[(1/x)]-x = (xe-1)e-x = xex or x to the power x
QED
RE: Simple maths
Cheers,
-- drej --
RE: Simple maths
RE: Simple maths
Thus:
[(1/x)]-x=(1/x)^-x ????
RE: Simple maths
RE: Simple maths
That's x[sup]x[/sup]
Good Luck
johnwm
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RE: Simple maths
[(the inverse of x)] - x
or
1
--- - x
x
This is clearly shown by the square brackets.
RE: Simple maths
For your updated definition, what exactly are you looking for? The only other plausible output is:
(1-x2)/x
Not sure if that's any simpler
TTFN
RE: Simple maths
(1/x)-x = ?
to
(1/x) = x
so
1/x = x
Thus:
x=1.
There is only a point solution to this equation. And I'm wondering what sort of engineer cant do algebra.
RE: Simple maths
This seems simplistic, multiply through both sides by x to clear the inverse and get:
1 - x^2 = x^2
to which adding x^2 to both sides would ultimately result:
1 = 2 x^2
I would get x = sqrt(1/2) = +/- 0.70711.
This assumes that you need (1/x) - x = x, perhaps a very big assumption.
Kenneth J Hueston, PEng
Principal
Sturni-Hueston Engineering Inc
Edmonton, Alberta Canada
RE: Simple maths
(1/x)-x = ? equivalent to (1/x)-x = 0? Only when ?=0, right?
RE: Simple maths
I hereby apologize to anyone I've offended. Esp. Drej, because I didn't do any better with my substitution of 0 for ?.
As da Cockroach states there is another interpretation.. It's still just algebra though...
RE: Simple maths
-(x+1)(x-1)/x
(1-x^2)/x (as mentioned above)
RE: Simple maths
{1/x}-x is not an equation; it is simply an expression.
What is wrong with 1/x-x?
Do you want another?
(1-x^2)/x
If you think that simplifies the expression, then go for it.