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Validation of Equation

Validation of Equation

Validation of Equation

(OP)
Wattage required to heat material:  

Weight of material (lbs) x Specific Heat (Btu/lb °F) x Temperature rise (°F)/3.412 btu/watt hr. x  Heat-up time (hr.)

 = Watts

I found this on a website, does this fly with you guys?  My heat transfer book has nothing on this.

RE: Validation of Equation

And how does this equation address the heat losses during heating?

TTFN

RE: Validation of Equation

(OP)
It doesnt I guess, but thats ok, for my needs I can use a worst case scenario.  So you agree with this equation(assuming no heat loss during heating)?

RE: Validation of Equation

(OP)
let me rewrite the equation

(W*Cp*Delta T)/(3.412*Time)

RE: Validation of Equation

By ignoring losses, you don't have "worst case scenario"

TTFN

RE: Validation of Equation

(OP)
I am trying to figure out the maximum temperature increase in the material.  So If I assume no heat is lost then wouldnt that give me the maximum temperature increase possible?

RE: Validation of Equation

(OP)
Ok, I just found this in my thermo book, Q=mCp(Ti-Tf)/time

so I believe it now.

RE: Validation of Equation

You've got the time multiplied instead of divided in your original post.

RE: Validation of Equation

Energy/time = power

TTFN

RE: Validation of Equation

In the original formula, time is indeed multiplied, but it is in the denominator. Parenthesizing it would have clarified the imbroglio.

Heat/(surface×time) = heat flux.

RE: Validation of Equation

You have to be real careful with this calculation.
The literature starts with Laplace's famous diffusion equation that diffusivity in square meters per second is equal to the quantity conductivity K divided by specific heat (thermitivity c) in joules per kilogram per degree C or K divided by density.

But research since that time, including Einstein has shown other variables are involved. It is an oversimplification.
Moisture and geometry are huge influences. When you say to heat a plate for instance, this equation assumes you heat it from both sides. It all changes when you heat from one side, and that is just for a slab or thin film with constant K coefficient, no wave or drop in surface temperature or emissivity or reflection or....

RE: Validation of Equation

To summarize, Laplace said Power=diffusivity* area * temperature change.
Einstein in his Kinetic Theory of Matter said that calories are a measure of heat energy, time to heat being proportional to the capacity of the molecules to contain the heat.  Temperature is the 1/2 Mass times velocity squared.  The english system has the same units for heat energy values, that is 1BTU is 1 calorie, it is only for converting between them that we need .293 times BTU's to get a calorie. For a long time dimensionless factors were used for losses.  Now that is changing.  See www.thermcoat.com. Also you often see 1.73 used to convert between watts and btu conductivity. Actually, that is 1.73 BTU's per foot converted to watt per foot.  This is only a lengthwise heat path with no diffusion or sideways movement of heat.  So, you don't see this factor in the downloaded model, just so you know it goes beyond simple conversion factors.  Also when you say maximum, that usually means that there is some efficiency factor, as used often in injection molding calculations of how much heat to use to heat so many pounds of plastic so many degrees in so much time. Again, that is a dimensionless model to simplifiy the physics.

RE: Validation of Equation

A time rate of increase or decrease either in mass or in the temperature is missing. Cp is assume constant for a temperature range.
Equat. s/b q=(1/3.412)*M*Cp*dT/dt or (1/3.412)*dM/dt*cp*dT.

RE: Validation of Equation


Which validates the formula by rwsasser1.

To chicopee, your comment is right. However, we shouldn't forget (1/3.412) is not an all-embracing factor since it only applies when converting Btu to watt-hour.

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