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liquid thermal expansion calc - help needed

liquid thermal expansion calc - help needed

(OP)
I have density data that shows this liquid is 55.9 lb/ft3 at 200'F and 53.7 lb/ft3 at 300'F. What is the thermal expansion coefficient (beta)?

I have tried inverting the density adn calculating (0.0186-0.0179)/100 = 0.000007 but that number seems too small compared to similar fluids. What is the right way to do this?

TYIA,

Heater Guy

RE: liquid thermal expansion calc - help needed

The equation for thermal expansion of any substance is given by

B = 1/V ( dV/ T)

where B = thermal expansion coefficient, V = Volume, dV = change in Volume, and T = change in temperature.

Your method looks right.  Have you checked the units?

RE: liquid thermal expansion calc - help needed

...because it should be [(0.0186-0.0179)/0.0179]/100 = 0.00039

beta = (dV/V0)/dT (PS: I am using d instead of delta and this is not a differentiation)

RE: liquid thermal expansion calc - help needed

Dean,

It seems we have posted at the same time.

RE: liquid thermal expansion calc - help needed


I hope heaterguy is now satisfied with the cubic thermal expansion value estimated by quark in 1/oF. When using oC the result should be multiplied by 1.8 .

RE: liquid thermal expansion calc - help needed

(OP)
Thank you. Your responses were sent to my spam. Sorry it took so long to reply. Quark answered my question.

RE: liquid thermal expansion calc - help needed

heaterguy:
The information you provided is not enough to calculate the term BETTA.  Unless, the pressure at the two conditions is the same.

RE: liquid thermal expansion calc - help needed


In theory sailoday28 is right. The definition of the cubic thermal expansion β, sometimes called alpha, is:

β = (1/V)(∂ V/∂ T)P

However, the isothermal compressibility values  

κ = -(1/V)(∂ V/∂ P)T

are quite small when the liquids are well below their normal boiling points, usually lower than 2×10-4/atm, to sensibly affect the definition given by quark.

RE: liquid thermal expansion calc - help needed

25362 (Chemical)
Can you explain in layman terms--How did you display the partials?
Thanks

RE: liquid thermal expansion calc - help needed

heaterguy
Knowing the liquid might give more of a handle on determining Betta.

RE: liquid thermal expansion calc - help needed

To sailoday28. It's easy: via the Process TGML at the end of your message, look down for TGML Character Entity Reference. There you"ll find the answer to your query.

RE: liquid thermal expansion calc - help needed

Another useful expression for β would be:

ρ /Δt)(1/ρave)

which in this case would result in:

β = [(55.9-53.7)/100][1/(55.9+53.7/2] = 0.0004/oF

RE: liquid thermal expansion calc - help needed

(OP)
25362,

I was using either of the densities, but it makes more sense to use the average of the two. Thanks.

heaterguy

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