kW calculation
kW calculation
(OP)
I am trying to comfirm the kW useage of a 3 phase system.
Each leg is 280 volts drawing 1300 amps.
Volts = 1.732 * 280 =485
P = (1.732 * 485 * 1300 *.9)1000 = 982.8 kW
Is this correct?
Each leg is 280 volts drawing 1300 amps.
Volts = 1.732 * 280 =485
P = (1.732 * 485 * 1300 *.9)1000 = 982.8 kW
Is this correct?





RE: kW calculation
RE: kW calculation
so (if current is balanced) three phases are using:
Power(W)= 3 * p.f. * Current * Voltage (L-N)
Power(VA)= 3 * Current * Voltage (L-N)
RE: kW calculation