×
INTELLIGENT WORK FORUMS
FOR ENGINEERING PROFESSIONALS

Log In

Come Join Us!

Are you an
Engineering professional?
Join Eng-Tips Forums!
  • Talk With Other Members
  • Be Notified Of Responses
    To Your Posts
  • Keyword Search
  • One-Click Access To Your
    Favorite Forums
  • Automated Signatures
    On Your Posts
  • Best Of All, It's Free!
  • Students Click Here

*Eng-Tips's functionality depends on members receiving e-mail. By joining you are opting in to receive e-mail.

Posting Guidelines

Promoting, selling, recruiting, coursework and thesis posting is forbidden.

Students Click Here

Jobs

Clamping Force

Clamping Force

Clamping Force

(OP)
This is a simple clamping force problem that I just want to be sure I am envisioning it correctly.  If you have a plate with one bolt in it torqued to a value X, the clamping force will be Y.  If you then add 3 more bolts torquing them all to the same value X, the total clamping force will still be Y since they are acting in parallel (in other words, it is distributing the clamping force along the plate rather than increasing the total clamping force).  Is that correct?  

RE: Clamping Force

Correct. The clamping force is independent of the number of fasteners. The service load on each fastener is a different matter, and would depend on the type of loading, clamping force per fastener and number of fasteners.

RE: Clamping Force

Where are you measuring the "clamping force"?  If you are trying to separate the plate from another piece, you must extert 4Y (assuming an ideal system).

Regards,

Cory

Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.

RE: Clamping Force

(OP)
The exact problem I am having is dealing with a clamp band.  The band is is broken into two 180 degree sections with a bolt torqued to X on each side.  I was trying to solve for the vertical clamping force since clamp band is tapered on the inside.  My approach was as follows

sigma(hoop)* Clamp Band Cross-Sectional Area = Internal Pressure * Area the pressure is acting on

Therefore,

Clamping Force = Internal Pressure * Area the pressure is acting on

I then solved for the internal pressure, did some good ole trig to get the vertical component, and called it a day.  My concern is if the Clamping Force I use on the left side of the equation is suppose to be double since there are two bolts.  I have talked myself into say yes and no.  If you draw the FBD it appears as if you need to take 2 * the clamping force since you have one on each side.  But realistically, I don't think that is the case but cannot prove it.  If this does not make sense, ignore the tapered part and solve it as a simple clamp band and determine the resulting clamping force if bolted together.  Thanks for your help.

RE: Clamping Force

If you are assuming the fasteners are not prestressed, then the resisting force each one exerts to withstand the internal pressure is 0.5 * Clamping Force (as defined above).

Regards,

Cory

Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.

Red Flag This Post

Please let us know here why this post is inappropriate. Reasons such as off-topic, duplicates, flames, illegal, vulgar, or students posting their homework.

Red Flag Submitted

Thank you for helping keep Eng-Tips Forums free from inappropriate posts.
The Eng-Tips staff will check this out and take appropriate action.

Reply To This Thread

Posting in the Eng-Tips forums is a member-only feature.

Click Here to join Eng-Tips and talk with other members!


Resources