Clamping Force
Clamping Force
(OP)
This is a simple clamping force problem that I just want to be sure I am envisioning it correctly. If you have a plate with one bolt in it torqued to a value X, the clamping force will be Y. If you then add 3 more bolts torquing them all to the same value X, the total clamping force will still be Y since they are acting in parallel (in other words, it is distributing the clamping force along the plate rather than increasing the total clamping force). Is that correct?





RE: Clamping Force
RE: Clamping Force
Regards,
Cory
Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.
RE: Clamping Force
sigma(hoop)* Clamp Band Cross-Sectional Area = Internal Pressure * Area the pressure is acting on
Therefore,
Clamping Force = Internal Pressure * Area the pressure is acting on
I then solved for the internal pressure, did some good ole trig to get the vertical component, and called it a day. My concern is if the Clamping Force I use on the left side of the equation is suppose to be double since there are two bolts. I have talked myself into say yes and no. If you draw the FBD it appears as if you need to take 2 * the clamping force since you have one on each side. But realistically, I don't think that is the case but cannot prove it. If this does not make sense, ignore the tapered part and solve it as a simple clamp band and determine the resulting clamping force if bolted together. Thanks for your help.
RE: Clamping Force
Regards,
Cory
Please see FAQ731-376 for tips on how to make the best use of Eng-Tips Fora.